Ohm's law without the boring part
By Mihai Dumitru · 11 October 2026 · 6 min read
On this page
Ohm's law is three letters: V = I × R. Most people learn it for a test, pass, and never really get it. Here's the version that sticks.
Start with the playground. Move the sliders and watch the dots. Faster dots means more current.
Ohm's law playground
Move the sliders. Watch what the current does. Then use the calculator below.
- Current = V ÷ R
- 19.1 mA
- Power = V × I
- 172 mW
Calculator: what do you want to find?
- Answer: current
- 20 mA
Push, squeeze, flow
- Voltage (V, volts) is the push. A 9 V battery pushes harder than a 1.5 V one.
- Resistance (R, ohms, Ω) is how hard the path pushes back.
- Current (I, amps) is how much actually flows. It's the result. You don't set it directly, you get it from the other two.
So: more push, more current. More resistance, less current. That's the whole idea. If it doesn't feel obvious yet, play with the sliders a bit more. Double the voltage and the current doubles. Double the resistance and it halves.
Three versions, one formula
- V = I × R when you want the voltage
- I = V ÷ R when you want the current
- R = V ÷ I when you want the resistance
You only need to remember the first one. The other two are the same thing moved around.
Watch the units
This is where almost every mistake happens. The formula works in volts, amps and ohms. Not milliamps, not kilohms. Convert first, then calculate.
- 20 mA = 0.02 A
- 4.7 kΩ = 4,700 Ω
- 1 MΩ = 1,000,000 Ω
Example: 9 V across 4.7 kΩ. 9 ÷ 4,700 = 0.0019 A, so about 1.9 mA. Divide 9 by 4.7 instead and you get 1.9 A, a thousand times wrong. The calculator in the playground takes 4.7k directly, so you can check yourself.
Three real examples
How much current flows?
5 V across a 220 Ω resistor. I = 5 ÷ 220 = 0.0227 A, about 23 mA.
Which resistor do I need?
You have 12 V and want about 50 mA. R = 12 ÷ 0.05 = 240 Ω. That's not a standard value, so take the next one up, 270 Ω. Now I = 12 ÷ 270 ≈ 44 mA. Close enough, and on the safe side.
What voltage is across it?
15 mA through 1 kΩ. V = 0.015 × 1,000 = 15 V. Now say your supply is only 9 V. Then 15 mA through 1 kΩ can't happen. The current will be lower, 9 mA at most. Ohm's law is also good for catching numbers that don't make sense.
Don't forget power
Power is how much energy turns into heat: P = V × I. 9 V and 20 mA gives 0.18 W. A 1/4 W resistor handles that, but it gets warm.
Put 12 V on a 10 Ω resistor and you get 1.2 A and 14.4 W. A small resistor in that spot will smoke. That's why every resistor has a power rating, and why the playground shows power next to current.
Where Ohm's law stops working
It works for resistors and wires. It doesn't work directly for LEDs, diodes and transistors. Their resistance changes with the voltage, so there's no single R to put in the formula.
That's exactly why an LED needs a resistor in front of it. The resistor follows Ohm's law, the LED doesn't. More on that in why your LED needs a resistor.
In VoltTrial, wire a battery and a resistor, press Run and tap the pins. The voltage and current you read are Ohm's law, live. Change the resistor and check the new numbers with the calculator above.
Try it in VoltTrialRead next
- Why your LED needs a resistor (and which one to use)Put an LED straight on a battery and it dies. Here's why, and a calculator that tells you the exact resistor.
- Resistor colour codes: read them in 10 secondsTap the bands on an interactive resistor, or type a value and get the colours. Plus the easy way to remember them.
- Series and parallel resistors, without the headacheSame parts, two ways to connect them, very different results. Add resistors and see where the current goes.